430=-16t^2-2t+763

Solution for 430=-16t^2-2t+763 equation:

430=-16t^2-2t+763

We move all terms to the left:

430-(-16t^2-2t+763)=0

We get rid of parentheses

16t^2+2t-763+430=0

We add all the numbers together, and all the variables

16t^2+2t-333=0

a = 16; b = 2; c = -333;
Δ = b2-4ac
Δ = 22-4·16·(-333)
Δ = 21316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21316}=146$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-146}{2*16}=\frac{-148}{32}
=-4+5/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+146}{2*16}=\frac{144}{32}
=4+1/2
$